jamf 判断是否是简单密码 自己亲自做的 有大用 有大大用

passwords=("1234" "0000" "1111"  "2222" "3333" "4444" "5555" "6666" "7777" "8888" "9999" "aaaa" "abcd" "12345"  "00000" "11111"  "22222" "33333" "44444" "55555" "66666" "77777" "88888" "99999" "aaaaa" "abcde" "admin" "123456"  "000000" "111111"  "222222" "333333" "444444" "555555" "666666" "777777" "888888" "999999" "aaaaaa" "abcdef"  "admin1" "1234567"  "0000000" "1111111"  "2222222" "3333333" "4444444" "5555555" "6666666" "7777777" "8888888" "9999999" "aaaaaaa" "abcdefg"  "admin12" "12345678"  "00000000" "11111111"  "22222222" "33333333" "44444444" "55555555" "66666666" "77777777" "88888888" "99999999" "aaaaaaaa" "abcdefgh"  "admin123" "123456789"  "000000000" "111111111"  "222222222" "333333333" "444444444" "555555555" "666666666" "777777777" "888888888" "999999999" "aaaaaaaaa" "abcdefghi"  "admin1234" "1990" "2000" "1989" "qwerty" "password" "love" "sunshine" "football" "abcabc" "123123" "1234567890" "admin" "user" "guest" "qwerty" "monkey" "dragon" "zxyz" "abcd1234"  "5201314" "1314520" "passwd" "guest" "letmein" "welcome" "asdfgh" "zxcvbn" "qazwsx" "azerty")

ALLUSERS=`dscl . -list /Users | grep -v '_'  | grep -v 'daemon\|nobody\|root'`

for p in "${passwords[@]}"; do

    for one_user in $ALLUSERS ; do

        dscl . -authonly "$one_user"  "$p" > /dev/null 2>&1

        if [ $?  =  0 ];then            

      echo "<result>simple_password</result>"

            exit 0

        fi

    done    

echo "<result>complex_password</result>"

exit 0